y=3^2logx+7 then d/dx=
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Y = 3^(2logx +7)
dY/dx = d/dx{ 3^(2logx+7) }
= log(3) . 3^(2logx+7) . d/dx (2logx+7)
= log(3) . 3^(2logx+7) . (2. 1/x + 0)
= log(3) . 3^(2logx+7) . 2/x
= {2 . log(3) . 3^(2logx+7)} / x (ans.)
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