Question

y – 3)/4 + (y – 1)/5 – (y – 2)/3 = 1
(3x – 2)/3 + (2x + 3)/3 = (x + 7)/6
(8y – 5)/(7y + 1) = -4/5
(5 – 7y)/(2 + 4y) = -8/7. Solve these linear equations..pls answeerrr fasssttt​ properly srep by step explanation

Answer 1

Answer:

Step-by-step explanation:

Question 1:

Find the common factors of the given terms.

(i) 12x, 36          (ii) 2y, 22xy         (iii) 14pq, 28 p2 q2      (iv) 2x, 3x2, 4       (v) 6abc, 24ab2, 12a2 b  

(vi) 16x3, -4x3, 32x            (vii) 10pq, 20qr, 30rp             (viii) 3x2 y3, 10x3 y3, 6 x2 y2 z

Answer:

(i) 12x = 2 * 2 * 3 * x  

    36 = 2 * 2 * 3 * 3

Hence, the common factors are 2, 2 and 3 = 2 * 2 * 3 = 12      

(ii) 2y = 2 * y

    22xy = 2 * 11 * x * y

Hence, the common factors are 2 and y = 2 * y = 2y    

(iii) 14pq * 2 * 7 * p * q

     28 p2 q2 = 2 * 2 * 7 * p * p * q * q

Hence, the common factors are 2 * 7 * p * q = 14pq  

(iv) 2x =2 * x * 1

     3x2 = 3 * x * x * 1

     4 = 2 * 2 * 1

Hence, the common factors is 1    

(v) 6abc = 2 * 2 * a * b * c

    24ab2 = 2 * 2 * 3 * a * a *b

   12a2 b = 2 * 2 * 3 * a * a * b

Hence, the common factors are 2 * 3 * a * b = 6ab

(vi) 16x3 = 2 * 2 * 2 * 2 * x * x * x

     -4x3 = (-1) * 2 * 2 * x * x * x

     32x = 2 * 2 * 2 * 2 * 2 * x

Hence, the common factors are 2 * 2 * x = 4x

(vii) 10pq = 2 * 5 * p * q

       20qr = 2 * 2 * 5 * q * r

      30rp = 2 * 3 * 5 * r * p

Hence, the common factors are 2 * 5 = 10

(viii) 3x2 y3 = 3 * x * x * y * y * y  

       10x3 y3 = 2 * 5 * x * x * x * y * y * y

       6 x2 y2 z = 2 * 3 * x * x * y * y * z

Hence, the common factors are x * x * y * y = x2 y2