Question

y^=3+4y solve complete square method

Answer 1

Answer:

answer for the given problem is given

Answer 2

Given:-

y² = 3 + 4y

Solution:-

• Completing Square method

y² = 3 + 4y

y² - 3 - 4y = 0

y² - 4y - 3 = 0

here (4/2)² = 2² +-4

•°• y² - 4y + 4 - 4 - 3 = 0

(y² - 4y + 4) - 4 - 3 = 0

(y - 2)² - 7 = 0

(y - 2)² = 7

y - 2 = +-√7

y - 2 = √7 or y - 2 = -√7

y = 2 + √7 or y = 2 - √7

More information:-

When equation is in the form x² + b x + c = 0, it can be written as

=> x² + bx + (b/2)² - (b/2)² + c = 0 that is,

(x + b/2)² = (b/2)² - c