Math, asked by janagamsunayani278, 10 days ago

y^3-6y^2-11y-6 /y^2-4y+3​

Answers

Answered by Ishita6006
0

Answer:

y

3

−6y

2

+11y−6=0

y

3

−3y

2

−3y

2

+9y+2y−6=0

(y

2

−3y+2)(y−3)=0

(y−1)(y−2)(y−3)=0

∴y=1,2,3

Step-by-step explanation:

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Answered by mirage2402
0

Answer:

Step-by-step explanation:

y  

3

−6y  

2

+11y−6=0

y  

3

−3y  

2

−3y  

2

+9y+2y−6=0

(y  

2

−3y+2)(y−3)=0

(y−1)(y−2)(y−3)=0

∴y=1,2,3

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