y = 3/8 (x) + 3/8 sin x cos x + 1/4 cos^3(x)sin x find dy/dx
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Answer:
3(cosx+sinx)−2(cos
3
x+sin
3
x)=8
⇒3cosx+3sinx−2cosx(1−sin
2
x)−2sinx(1−cos
2
x)=8
⇒cosx+sinx+2cosx.sinx(sinx+cosx)=8
⇒(cosx+sinx)(1+2cosx.sinx)=8
⇒(cosx+sinx)(sin
2
x+cos
2
x+2cosx.sinx)=8
⇒(cosx+sinx)
3
=8⇒cosx+sinx=2
but we know, sinx+cosx≤
2
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