Question

y+3/y-2 - 1-y/y =17/4, y not =0.2 find y​

Answer 1

Answer:

• Step-by-step explanation:

1.       Idk in what state of mind sadiaanam wrote the answer

Answer 2

The value of y is 4 or -2/9.

Given:

• $\frac{y + 3}{y - 2} - \frac{1 - y}{y} = \frac{17}{4} \: y \neq \: 0.2$

To find:

• Find the value of y.

Solution:

Step 1:

Simplify the equation.

$\frac{y + 3}{y - 2} - \frac{1 - y}{y} = \frac{17}{4}$

$\frac{y(y + 3) - (1 - y)(y - 2)}{y(y - 2)} = \frac{17}{4}$

$\frac{ {y}^{2} + 3y - (3y - 2 - {y}^{2})}{ {y}^{2} - 2y} = \frac{17}{4}$

$\frac{ {y}^{2} + 3y - 3y + 2 + {y}^{2}}{ {y}^{2} - 2y} = \frac{17}{4}$

$\frac{ 2{y}^{2} + 2 }{ {y}^{2} - 2y} = \frac{17}{4}$

$4( 2{y}^{2} + 2 ) = 17( {y}^{2} - 2y)$

$8 {y}^{2} + 8 = 17 {y}^{2} - 34y$

$\bf 9 {y }^{2} - 34y - 8 = 0$

Step 2:

Simply the quadratic equation.

$9 {y }^{2} - 34y - 8 = 0$

$9 {y}^{2} - 36y + 2y - 8 = 0$

$9y(y - 4) + 2(y - 4) = 0$

$(y - 4)(9y + 2) = 0$

$y - 4 = 0$

or

$\bf y = 4$

or

$9y + 2 = 0$

$\bf y = - \frac{2 }{9}$

Thus,

The value of y is 4 or -2/9.

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