Question

(y+3)(y^2-3y+9) what is the product?

Answer 1

Answer:

(y+3)(y^2-3y+9)

= y^3 - 3y^2 + 9y + 3y^2 - 9y + 27

= y^3 + 27

Answer 2

Step-by-step explanation:

$= > (y + 3)( {y}^{2} - 3y + 9) \\ = > {y}^{3} - 3 {y}^{2} + 9y + 3 {y}^{2} - 9y + 27 \\ = > - 2 {y}^{2} + 3 {y}^{2} + 9y - 9y + 27 \\ = > {y}^{2} + 27$

So the product is y²+27.