Question

(y+3) (y-3) -y(y+5) = 6

Answer 1

(y+3)(y-3)-y²-5y=6
y²-3y+3y-9-y²-5y=6
-9-5y=6
-5y=6+9
y=15/-5
y=-3

Answer 2

Answer:

The value of y is -3.

Step-by-step explanation:

An equation with a polynomial set to zero is referred to as a polynomial equation. It is an equation made up of coefficients, non-negative integer exponents, variables, and operations. It also contains the equal sign. Different exponents exist for it. The degree of the equation is revealed by the highest one.

The process of solving polynomial equation p(x) = 0 is nothing but finding the value(s) of 'x' that satisfies the equation. A number 'a' is known as a 'zero' of a polynomial p(x) if and only if p(a) = 0. Here, 'a' is also known as the root of the polynomial equation p(x) = 0. Hence, the process of solving polynomial equations is nothing but finding its roots.

Given: $(y+3) (y-3) -y(y+5) = 6$

Find: Solve the polynomial equation.

We know (a-b)(a+b)$=a^2-b^2$

$(y+3) (y-3) -y(y+5) = 6\\y^2-9--y(y+5) = 6$

$y^{2} -9-y^{2} -5y=6\\-9-5y=6\\-5y=6+9\\-5y=15\\y=-3$

Hence, the value of y is -3.

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