Question

(y+3) (y-3) -y(y+5)=6 solve it and be serious exam is near and mine is ble don't write anything in comment I need real answer I am so weak in math​

Answer 1

(y+3) (y-3) -y(y+5)=6

let us first solve (y+3) (y-3)

y^2-3y+3y-9

cancel +3y and -3y

y^2 -9 -y(y+5)=6

y^2 -9 -y^2-5y=6

cancel y^2 and -y^2

-9 -5y=6

-5y = 6+9

-5y = 15

y = 15/-5

therefore y = -3

hope it helps you

Answer 2

answer

y=3/5

explanation

(y+3)(y-3)-y(y+5)=6

y^2-3^2-y^2-5y=6. [using formula (a+b)(a-b)=a^2-b^2)[multiple -y to other terms]

now y^2and -y^2 will cancel out each other due to opposite signs

we will get 9-5y=6

now shift 9 to other side we get -5y= -3 as by shifting 9 will become-9

now cancel minus on both sides we get 5y = 3 shift 5 to other side it will. get divided to 3 and we get. y = 3/5 as final answer..

Hope this will help you....