Math, asked by srijans2008, 3 months ago

( y + 3 ) ( y² + 2y -1​

Answers

Answered by Anonymous
4

Answer:

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Step-by-step explanation:

Factorise :

y

3

3

y

2

+

2

y

6

x

y

+

3

x

Solution

Given that:

y

3

3

y

2

+

2

y

6

x

y

+

3

x

=

(

y

3

3

y

2

)

+

(

2

y

6

)

+

(

x

y

+

3

x

)

, (group pair of terms)

=

y

2

(

y

3

)

+

2

(

y

3

)

x

(

y

3

)

, (factor each binomials)

=

(

y

3

)

(

y

2

+

2

x

)

, (factor out common factor

(

y

3

)

)

The common factors of

y

3

3

y

2

+

2

y

6

x

y

+

3

x

are

(

y

3

)

(

y

2

+

2

x

)

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