Question

y= 3sin^2x - sin^3x
Differentiate the given function with respect to x

Answer 1

day/DX=3sin2x-3sin^2xcosx
just use chain rule

Answer 2

$y = 3 { \sin(x) }^{2} - { \sin(x) }^{3} \\ diff.w.r.x \\ \frac{dy}{dx} = 3 \times 2 \sin(x) \times \frac{d}{dx} ( \sin(x )) \\ \\ \: \: \: \: \: \: \: \: - 3 { \sin(x) }^{2} \times \frac{d}{dx} ( \sin(x)) \\ \: \: \: \: \: \: \: \: = 6 \sin(x) \cos(x) - 3 { \sin(x) }^{2} \cos(x) \\ \: \: \: \: \: \: \: \: = 3(2 \sin( x) \cos(x)) - { \sin(x) }^{2} \cos(x) ) \\ \: \: \: \: \: \: \: \: = 3( \sin(2x) - { \sin(x) }^{2} \cos(x))$
Here is the answer for your question.