Math, asked by Anonymous, 1 year ago

y=3x^2×loge^x make difference

Answers

Answered by yudhisthirjingar

0

Answer:

Step-by-step explanation:

If we differentiate the solution is:

dy/dx = 6x.log.e^x + 3x^2. e^x/e^x

dy/dx = 6x.log.e^x + 3x^2

your answer

6x.log.e^x + 3x^2

yudhisthirjingar: If we integrate answer we get the question...make a integrate....

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