Question

(Y-3x+3)dy/dx=2y-x-4

Answer 1

= x² y = (x³ + y³) (dy/dx)

= x² y/ (x³ + y³) = 1/((x/y)+(y²/x²)

OR

= dx/dy = (x/y)+(y²/x²)

ΦIntegrating with respect to y, x
= x log y + y³/(3 x²)

ΦThis on simplification will reduce to x³ = y³/3 (1 - log y)