y = 3x + 3
y = x − 1
Solve with substitution with steps please!
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3x+y+3 - eq (1)
x+y+1 - eq(2)
from eq 1
y=3x+3 - eq(3)
substituting eq 3 into eq 2
x+(3x+3)+1
x+3x-3+1
4x-2
4x=2
x=2
put this value in eq 3
y=3(2)+3
y=6+3
y=9
hence,x=2,y=9
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