Question

Y=3x^5-3x-1/x find dy/dx

Answer 1

Answer:

15x^4 - 3+ 1/x^2

Explanation:

In General,

if y=x^n, then dy/dx= nx^(n-1)

Y=3x^5-3x-1/x

  =3x^5-3x-(x^-1)

dy/dx= 5(3)x^4 - 3x^0- (-1)x^-2

         = 15x^4 - 3+ x^-2

        = 15x^4 - 3+ 1/x^2

Answer 2

Answer:

Value of $\frac{dy}{dx} \: is \: 15 {x}^{4} + \frac{1}{ {x}^{2} } - 3$

Explanation:

Given,

$y = 3 {x}^{5} - 3x - \frac{1}{x}$

We have to find dy/dx ( Find derivative of y with respect to x)

Doing derivative with respect to x,

$\frac{dx}{dy} = \frac{d}{dx} (3 {x}^{5} - 3x - \frac{1}{x} )$

$= \frac{d}{dx} (3 {x}^{5} ) - \frac{d}{dx} (3x) - \frac{d}{dx} ( {x}^{ - 1} )$

$= 5 \times 3 {x}^{4} - 3 \times 1 - ( - 1) \times {x}^{ - 2}$

$= 15 {x}^{4} + \frac{1}{ {x}^{2} } - 3$

Here applied formula,

$\frac{d}{dx} ( {x}^{a} ) = a {x}^{a - 1}$