y=3x+6;-2x+4y=4 solve the equation
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Answer:
y = 3x + 6
3x - y = 6-----------Eq 1
-2x + 4y = 4
-2 ( x - 2y ) = 4
x - 2y = 4/-2
x - 2y = -2------------Eq 2
From Eq 1 and Eq2,
3x - y = 6-----------Eq 1(multiply by 1)
x - 2y = -2------------Eq 2(multiply by 3)
3x - y = 6---------------Eq 3
3x - 6y = -6--------------Eq 4
Change signs ,
3x - y = 6
-3x + 6y = 6
Solve we get,
3x -3x + 6y - y = 6 + 6
0 + 5y = 12
5y = 12
y = 12/5
Now we can find the value of x by substituting the value of y in Eq 2,
3x - y = 6-----------Eq 1
3x - (12/5) = 6
3x = 6 + 12/5(take LCM as 5)
3x = (30+12)/5
3x = 42/5
x = 42/15
x = 14 / 5
Hope this helps you..............................
Plz mark me the brainliest as i took effort to type and work out this sum
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