Math, asked by nelsiti719, 11 days ago

Y=3x²-4x + 2 with respect to x

Answers

Answered by bhagimalani
0

Answer:

y′=limh→0f(x+h)−f(x)h" role="presentation" style="display: inline-table; font-style: normal; font-weight: normal; line-height: normal; font-size: 15px; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">=limh→0f(x+h)−f(x)hy′=limh→0f(x+h)−f(x)h

y′=limh→03(x+h)2–4(x+h)+2−(3x2–4x+2)h" role="presentation" style="display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 15px; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">y′=limh→03(x+h)2–4(x+h)+2−(3x2–4x+2)hy′=limh→03(x+h)2–4(x+h)+2−(3x2–4x+2)h

y′=limh→03x2+6xh+3h2−4x−4h+2−3x2+4x−2h" role="presentation" style="display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 15px; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">

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