Question

y-{4-3y}÷2y-{3+4y}=1/3​

Answer 1

$\huge\underline\mathfrak{Answer-}$

$\red{\sf{y=\dfrac{17}{22}}}$

$\huge\underline\mathfrak{Explanation-}$

$\sf\dfrac{y-(4-3y)}{2y-(3+4y)}$ = $\sf\dfrac{1}{5}$

$\hookrightarrow$ $\sf\dfrac{y-4+3y}{2y-3-4y}=\dfrac{1}{5}$

$\hookrightarrow$ $\sf{\dfrac{4y-4}{-2y-3}=\dfrac{1}{5}}$

By cross multiplying,

$\hookrightarrow$ $\sf{5(4y-4)=(-2y-3)}$

$\hookrightarrow$ $\sf{20y-20=-2y-3}$

$\hookrightarrow$ $\sf{20y+2y=-3+20}$

$\hookrightarrow$ $\sf{22y=17}$

$\hookrightarrow$ $\sf{\red{y=\dfrac{17}{22}}}$