Question

y+4/3y+7=1/2 solve and verify it. ​

Answer 1

$y + \frac{4}{3y} + 7 = \frac{1}{2}\\\frac{3y^{2} }{3y} + \frac{4}{3y} = \frac{1}{2} - \frac{14}{2}\\\frac{3y^{2} + 4}{3y} = - \frac{13}{2}\\ 2(3y^{2} +4) = -3y * 13\\6y^{2} + 39y + 8 = 0\\D = b^{2} - 4ac = 39^{2} - 4*6*8 = 1521 - 192 = 1329\\y_{1} = \frac{-39 - \sqrt{1329} }{2*6} = -6.2880 \\y_{2} = \frac{-39 + \sqrt{1329} }{2*6} = -0.21205$