Question

y=4 sin omega t + 3 sin omega t find amplitude

Answer 1

Answer:

We have x1=4,x2=3

So amplitude of simple harmonic motion is =root 4^2 +3^2

= root 25

Amplitude = 5

Answer 2

y = x(t) => 'y' is a sinusoidal function of 't'

Let 'm' = wt

--> x(t) = 3 sin m + 4 cos m

= 5 ( 3/5 sin m + 4/5 cos m )

= 5 sin ( m + arctan ( 4/3 ) )

= 5 sin ( wt + arctan ( 4/3 ) )

At 't' = 0 -->

--> x(m) = 5 sin( arctan (4/3) )

= 5 ( 0.8 ) = 4 ✓✓

=> Amplitude of SHM = 4