Question

y/4-y/3 = y/6+3/18 find the solution
​

Answer 1

Answer:

SOLVE FOR Y

y = 2/3 ≈ −0.666666667

The explanation is there in the pic as it was difficult for me to type it here

Answer 2

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

$\sf \dfrac{y}{4} - \dfrac{y}{3} = \dfrac{y}{6} + \dfrac{3}{18}$

LCM of 4 & 3 is 12 and on the right side 3/18 will be cancelled by 3.

$\sf \longmapsto \dfrac{3y - 4y}{12} = \dfrac{y}{6} + \dfrac{1}{6}$

$\sf \longmapsto \dfrac{ - y}{12} = \dfrac{y + 1}{6}$

Now,we will cross multiply to both sides.

6 gets multiply with -y and 12 with y+1

$\sf \longmapsto6 \times - y = 12 \times (y + 1)$

$\sf \longmapsto - 6y = 12y + 12$

$\sf \longmapsto - 6y = 12(y + 1)$

$\sf \longmapsto - y = 2(y + 1)$

$\sf \longmapsto - y = 2y + 2$

$\sf \longmapsto - y - 2y = 2$

$\sf \longmapsto - 3y = 2$

$\sf \bold{ \: y = - \dfrac{2}{3} }$

Check by putting y's values in Equation:

$\sf \longmapsto - \dfrac{y}{12} = \dfrac{y + 1}{6}$

$\sf \longmapsto \dfrac{ \dfrac{ - 2}{3} }{12} = \dfrac{ - \dfrac{2}{3} + 1}{6}$

$\sf \longmapsto - \dfrac{2}{3} \times \dfrac{1}{12} = \dfrac{ - 2 + 3}{ \dfrac{3}{6} }$

$\sf \longmapsto - \dfrac{1}{18} = - \dfrac{1}{18}$