Math, asked by 123RohithB321, 10 days ago

ʟɪꜱᴛ ᴀʟʟ ᴛʜᴇ ꜰᴏʀᴍᴜʟᴀꜱ ᴏꜰ ʟᴇꜱɴ ɪɴᴛʀᴏᴅᴜᴄᴛɪᴏɴ ᴛᴏ ᴛʀɪɢɴᴏᴍᴇᴛʀy ​

Answers

Answered by dishamalhan325
3

Step-by-step explanation:

sin (π/2 – A) = cos A & cos (π/2 – A) = sin A

sin (π/2 + A) = cos A & cos (π/2 + A) = – sin A

sin (3π/2 – A) = – cos A & cos (3π/2 – A) = – sin A

sin (3π/2 + A) = – cos A & cos (3π/2 + A) = sin A

sin (π – A) = sin A & cos (π – A) = – cos A

sin (π + A) = – sin A & cos (π + A) = – cos A

sin (2π – A) = – sin A & cos (2π – A) = cos A

sin (2π + A) = sin A & cos (2π + A) = cos A

hope it helps

Answered by gaurianushka987
1

Step-by-step explanation:

here is your answer dear

hope it help you a lot

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