y=(4x-1)^1/2 find dy/dx
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The answer is given below :
RULE :
d/dx (x^n)
= n x^(n - 1)
SOLUTION :
Given,
y = (4x - 1)^(1/2)
Now, differentiating both sides with respect to x, we get
dy/dx = 1/2 × (4x - 1)^(1/2 - 1) × d/dx (4x - 1)
= 1/2 × (4x - 1)^(-1/2) × 4
= 2 × (4x - 1)^(-1/2)
= 2/{√(4x - 1)}
Thank you for your question.
RULE :
d/dx (x^n)
= n x^(n - 1)
SOLUTION :
Given,
y = (4x - 1)^(1/2)
Now, differentiating both sides with respect to x, we get
dy/dx = 1/2 × (4x - 1)^(1/2 - 1) × d/dx (4x - 1)
= 1/2 × (4x - 1)^(-1/2) × 4
= 2 × (4x - 1)^(-1/2)
= 2/{√(4x - 1)}
Thank you for your question.
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