y=4x+7
4x+11y+7=0 find -intercept of two lines
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Answer:
Step-by-step explanation:
Given lines are 2x+11y−7=0 and x+3y+5=0
⇒y=−
11
2
x+
11
7
and y=−
3
1
x−
3
5
Their, slopes are m
1
=−
11
2
and m
2
=−
3
1
Therefore, angle between lines is
tanθ=
1+m
1
m
2
m
1
−m
2
=
1+
11
2
×
3
1
−
11
2
+
3
1
=
35
5
Thus θ=tan
−1
(
7
1
)
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