Question

y''+4y'+8y=sinx. question bta fo koi​

Answer 1

Step-by-step explanation:

Homogenous part:

y''+4y'+8y=0

y=e^(rx)

===> e^(rx) ( r^2 + 4r +8)=0

r= -2 ± 2i

y= e^(-2x) (cos(2x)+sin(2x) )

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