Question

y=5x-3 -x-5y=-11
how​

Answer 1

Answer:

Let the equation

5x− 3y= 11 ----- (i)

10x+ 6y= −22 ----- (ii)

From (i)

y=

3

5x−11

put the value of y in (ii)

10x+ 6(

3

5x−11

)= −22

30x+ 30x− 66= −66

x= 0

put

x=

0

in (i), we get

0− 3y= 11

y=−

3

11

Step-by-step explanation:

Hi.....

Hope it helps you.....

Answer 2

Step-by-step explanation:

Question -

Solve the following pair of linear equations by substitution method -

y = 5x-3 and - 5y= - 11

Solution -

Given equations,

y = 5x-3........1)

and,

-5y = - 11........2)

Now,substituting the value of y in equation 2) we will get -

=> - 5(5x-3) = - 11

=> - 25x +15= - 11

=> - 25x = - 11-15

=> - 25x = - 26

=> x= \frac{-26}{-25} x=

−25

−26

=> x = \frac {26}{25}x=

25

26

Now substituting the value of x in equation 1)we will get -

\implies \: y = 5 \times \frac{26}{25} - 3⟹y=5×

25

26

−3

⟹y = \frac{26}{5} - 3⟹y=

5

26

−3

⟹y = \frac{26 - 15}{5} ⟹y=

5

26−15

⟹y = \fraction{11}{5} ⟹y=

5

11

Therefore the value of x is\:\fraction {26}{25} \:\:and\:\: y\: is \:\fraction {11}{5}Thereforethevalueofxis

25

26