Question

y=6sinx logbase10 x + e to find dy/dx?

Answer 1

I suppose your question is $y = 6sin(x) log_{10} (x+e)$. Then convert $log_{10}(x+e)$ to $\frac{log_{e}(x+e)}{log_{e}10}$. Use product rule, you get this $\frac{dy}{dx} = \frac{6}{log_{e}10}(cos(x)log_{e}(x+e)+\frac{sin(x)}{x+e})$