Question

y = –6x+2 –12x – 2y = –4 How many solutions does this linear system have? one solution: (0, 0) one solution: (1, –4) no solution infinite number of solutions

Answer 1

Thank you for asking this question. Here is your answer:

y = -6x + 2 . . . . . . . . (1)

-12x - 2y = -4 . . . . . . (2)

Putting (1) into (2), we have

-12x - 2(-6x + 2) = -4

-12x + 12x - 4 = -4

-4 = -4

If there is any confusion please leave a comment below.

Answer 2

Answer:

The system of equations have infinite number of solutions.

Step-by-step explanation:

We have been given the system of equations

$y=-6x+2......(1)\\-12x-2y=-4.......(2)$

On plugging the value of x from equation (1) in (2)

$-12x-2(-6x+2)=-4\\-12x+12x-4=-4\\-4=4$

We got -4 = -4 , which is always true.

Hence, the given system of equations have infinitely many solutions.  

Last option is correct.