Question

y+7/3=1+3y-2/5 find y in this sum please help​

Answer 1

Answer:

$\frac{y + 7}{3} = \frac{1 + 3y - 2}{5} \\ \\ \\ = 5(y + 7) = 3(1 + 3y - 2) \\ \\ = 5y - 35 = 3 + 9y - 6 \\ \\ = 5y - 35 = 9y - 3 \\ \\ = - 35 + 3 = 9y - 5y \\ \\ = - 32 = 4y \\ \\ = y = \frac{ - 32}{4} \\ \\ y = - 8$