× + y = 7 and 2× - 3y = 11 substituting method
can u all help me please
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Answer:
x+y=7.....eq1
2x-3y=11.....eq2
x+y=7
x=7-y.....eq3
now put eq 3. in eq 2
2x-3y=11
2(7-y)-3y=11
14-2y-3y
-5y=11-14
-5y=-3
5y=3
y=3/5......eq4
now put eq 4 in eq1
x+y=7
x+3/5=7
x=7-3/5
x=35-3/5
x=32/5
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