Question

y=(7x^3/x^2+1) find dy/dx​

Answer 1

Answer:

Find dy/dx y = natural log of 7x^3-x^2. y=ln(7x3−x2 ) y = ln ( 7 x 3 - x 2 ). Differentiate both sides of the equation. ddx(y)=ddx(ln(7x3−x2)) d d x ( y ) = d d