Math, asked by sk9102963662, 8 months ago

y=(7x^3/x^2+1) find dy/dx

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Answered by shafikurhindiclass

Answer:

Find dy/dx y = natural log of 7x^3-x^2. y=ln(7x3−x2 ) y = ln ( 7 x 3 - x 2 ). Differentiate both sides of the equation. ddx(y)=ddx(ln(7x3−x2)) d d x ( y ) = d d

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y=(7x^3/x^2+1) find dy/dx​

Answers

y=(7x^3/x^2+1) find dy/dx