Question

y"+8y'+16y=0 then y(x)= ?​

Answer 1

Answer:

Find the general solution to

y

′′

−

8

y

′

+

16

y

=

0

. Then, find the solution that satisfies the initial conditions

y

(

0

)

=

5

,

y

′

(

0

)

=

0

Answer 2

Answer:

y^2+24y=0

y(y+24)=0

y+24=0

y= -24