Question

y =a^1\2loga^cosx solveeee​

Answer 1

Answer:

$4 \sqrt{48 } - \sqrt{3} - 15 \sqrt{3}$

Answer 2

Answer:

We have,

$\sf \red{y \: = \: a½log^acosx}$

On differentiating both sides w.r.t x, we get,

$\bf \purple{\frac{dy}{dx} = a½\frac{1}{cos \: xlog↓ea} × \: - sin \: x}$

$\sf \green{\frac{dy}{dx} = a½\frac{tan \: x}{log↓ea}}$

$\mathfrak \red{Hence, \: {\frac{dy}{dx} = a½\frac{tan \: x}{log↓ea} \:is \: the \: answer}}$

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