Computer Science, asked by harikrishnan90431, 7 months ago

Y = A’B’C’D + AB’C’D + A’BCD + AB’CD + A’BCD

Answers

Answered by Anonymous
14

Answer:

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Explanation:

Since AND operation is commutative, the last term can be rewritten as A¯¯¯¯BC¯¯¯¯CBD¯¯¯¯ . This term would vanish because C¯¯¯¯C=0 . We are then left with A¯¯¯¯B¯¯¯¯CD+AB¯¯¯¯C¯¯¯¯D¯¯¯¯+A¯¯¯¯BC¯¯¯¯ which cant be simplified further.

I will assume that you meant this:

What is the simplified Boolean expression of A¯¯¯¯B¯¯¯¯CD+AB¯¯¯¯C¯¯¯¯D¯¯¯¯+A¯¯¯¯BC¯¯¯¯+A¯¯¯¯BC¯¯¯¯+BCD¯¯¯¯ ?

A¯¯¯¯B¯¯¯¯CD+AB¯¯¯¯C¯¯¯¯D¯¯¯¯+A¯¯¯¯BC¯¯¯¯+A¯¯¯¯BC¯¯¯¯+BCD¯¯¯¯

Convert above expression to Standard Sum of Products Form (SSOP). We get:

A¯¯¯¯B¯¯¯¯CD+AB¯¯¯¯C¯¯¯¯D¯¯¯¯+A¯¯¯¯BC¯¯¯¯D+A¯¯¯¯BC¯¯¯¯D¯¯¯¯+ABCD¯¯¯¯+A¯¯¯¯BCD¯¯¯¯

Plot a 4-variable K-map. After suitable grouping, we get:

Turns out the boolean expression cant be simplified further. So you get:

A¯¯¯¯B¯¯¯¯CD+AB¯¯¯¯C¯¯¯¯D¯¯¯¯+A¯¯¯¯BC¯¯¯¯+BCD¯¯¯¯

as the simplified expression.

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Answered by ananyasharma427
4

Answer:

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