Question

y = (a+c)(a+d)(b+c)(b+d) solve with boolean algebra

Answer 1

Answer:

y={a.a +a.d+c.a+c.d}{b.b+b.d+c.b+c.d}

Y={a(1+d+c)+c.d}{b(1+d+c)+c.d}

y={a+c.d}{b+c.d}

y={a.b +a.c.d+c.d.b+c.d.c.d.}

y={a.b+a.c.d+c.b.d+c.d.}

y={a.b+c.d(a+b+1)}

y={a.b+c.d.}

y=a.b+c .d