Physics, asked by dishantjain582, 9 months ago

Y
A
d
9. A long rectangular slab of transparent medium of
thickness d is placed on a table with length parallel to the
x-axis and width parallel to the y-axis. A ray of light is
travelling along y-axis at origin. The refractive index u of the
medium varies as we
Ho
where up and r(>1) are
1 - (x/r)
constants. The refractive index of air is 1.
(a) Determine the x-coordinate of the point A, where the
ray intersects the upper surface of the slab-air boundary.
(b) Write down the refractive index of the medium at A.
(c) Indicate the subsequent path of the ray in air
medium​

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Answers

Answered by dipnarayanyadav83
1

Explanation:

isko hindi me lekho na ham hindi i medium hae

Answered by Pratham2508
0

Question: A long rectangular slab of transparent medium of thickness d is placed on a table with length parallel to x-axis and width parallel to y-axis. A ray of light is traveling along y-axis at origin. The refractive index of the medium varies as, Vited. The refractive index of air is 1. The value of x, where the ray intersects the upper surface of the slab-air boundary is Glassy shade

Answer:

цSin∅=1*Sin∅=1/ц

tan∅=1/\sqrt[]{(miu^{2-1} )}=e^{\frac{-x}{2d} }

Derivative of y=\int\limits^a_b {e^{\frac{-x}{2d} } } \, dx

y=2d(1-e^{\frac{-x}{2d}) }

when y=d

x=dln4

ц=\sqrt[]{1+e^{\frac{x}{d} } }

the given graph in exponential when the ray intersect the upper surface of the slab-air boundary with ц=1

Thus, x=infinity

#SPJ3

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