Y=a log(kx-wt) where x and Y are distace then find the dimension of a,k and w.
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As sin function is dimensionless and wt- kx is dimensionless
now difference of two quantity ( wt) and ( kx) is dimensionless
therefore
wt= M0L0T0
=>w* time(T1) = M0L0T0
=>w= M0L0T0 / T1= M0L0T(-1)
also
kx= M0L0T0
=>k* distance(L1) = M0L0T0
=>k= M0L0T0 /L1=M0L(-1)T0
______________________________
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Follow me
______________________________
As sin function is dimensionless and wt- kx is dimensionless
now difference of two quantity ( wt) and ( kx) is dimensionless
therefore
wt= M0L0T0
=>w* time(T1) = M0L0T0
=>w= M0L0T0 / T1= M0L0T(-1)
also
kx= M0L0T0
=>k* distance(L1) = M0L0T0
=>k= M0L0T0 /L1=M0L(-1)T0
______________________________
Please vote me brainliest.
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