Math, asked by chongpi2148, 9 months ago

Y=a^sinx-cosx differentiate with respect to x

Answers

Answered by sreeh123flyback
0

Step-by-step explanation:

y =   {a}^{ \sin( \alpha )  -  \cos( \alpha ) }    \\   \frac{d( {a}^{x}) }{dx }  =  {a}^{x} . ln(a)  \\  \frac{dy}{dx}  =  {a}^{ \sin( \alpha )  -  \cos( \alpha ) }  \times  \cos( \alpha )  +  \sin( \alpha )  \times  ln(a)

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