Y=acosx+bsinx find d²y/dx²+y
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Given,
$ y = A cos nx + B sin nx $
Differentiating both sides with respect to x, we get
dy/dx = - nA sin nx + nB cos nx
Again, Differentiating with respect to x, we get
Step-by-step explanation:
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Y=acosx+bsinx find d²y/dx²+y
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