Question

Y=alog(a²/a²-x²) find dy/dx​

Answer 1

Answer:

Step-by-step explanation: we know log(a/b)=loga-logb=-[logb-loga]=-log(b/a) so,

Y=alog(a^2/a^2-x^2) = -alog(a^2-x^2/a^2)

Y= -alog(1- x^2/a^2)

dY/dx= -a/1-(x^2/a^2) multiplied by -2x/a^2

dY/dx= 2x/a[1-(x^2/a^2)]