Question

y = Asinx + Bcosx , then Proove that d²y/dx² + y = 0 ​

Answer 1

Hi !!

Solution : we have

dy/dx = Acosx - Bsinx

and , d²y/dx² = d(Acosx - Bsinx)dx

= -Asinx - Bcosx = -y

Hence, d²y/dx² + y = 0

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Hope it helps you !!!

@Raj❤

Answer 2

Answer:

PROVING :

Step-by-step explanation:

Refer the attached picture.