Y - axis divides the join of P (-4 , 2) and Q (8, 3) in what ratio
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Answered by
4
#BAL
First, we need an equation for the line joining these two points. To get this, start by calculating the slope:
m=y2−y1x2−x1=3−28+4=112
Then we can use the point-slope equation for a line: y−y1=m(x−x1)
or, using point P: y−2=112(x+4)
which simplifies to y=112x+73
Now we know that the intersection of the line segment PQ intersects the y-axis at the point (0,73). Let’s call this point R.
There are probably multiple ways to proceed from here, but what I did was calculate the lengths of PR and RQ, using the distance formula:
d=(y2−y1)2+(x2−x1)2−−−−−−−−−−−−−−−−−−√
The result is 2:1.
Answered by
3
Let the ratio be k:1
k 1
P——————Y(0,y)—————Q
(-4,2) (8,3)
=>0=8k-4/k+1
=>0=8k-4
=>4=8k
=>k=1/2
•Thus,The Ratio Is 1/2
k 1
P——————Y(0,y)—————Q
(-4,2) (8,3)
=>0=8k-4/k+1
=>0=8k-4
=>4=8k
=>k=1/2
•Thus,The Ratio Is 1/2
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