y axis divides the line segment joining a 2
2- 3 and B 5 - 6 in the ratio
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Answer:
Using the section formula, if a point (x,y) divides
the line joining the points (x
1
,y
1
) and (x
2
,y
2
) in the ratio m:n, then
(x,y)=(
m+n
mx
2
+nx
1
,
m+n
my
2
+ny
1
)
Substituting (x
1
,y
1
)=(2,−3) and (x
2
,y
2
)=(5,6) in the section formula,
we get the point (
m+n
m(5)+n(2)
,
m+n
m(6)+n(−3)
)
Since the point of intersection lies on the x - axis, y - coordinate =0
m+n
6m−3n
=0
=>6m−3n=0
=>6m=3n
2m=n
=>m:n=1:2
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