Question

Y axis divides the line segment joining the points P (-4,2) and Q (8,3) in the ratio?

Answer 1

>>The intersection of line with Y-axis then the point is (0,y)

Let the ratio be k:1

Using section formula,

>>(k*8+1*-4)/k+1=0

>>8k-4=0

>>k=1/2

Ratio = 1:2

Answer 2

Answer:

Required ratio is 1:2.

Step-by-step explanation:

Given,Y axis divides the line segment joining the points P (-4,2) and Q (8,3)

Using the section formula,if a point (x,y) divides the line joining the points $(x_1,y_1)$and $(x_2,y_2)$in the ratio m:n,then

$(x,y) = ( \frac{mx_2 + nx_1}{m + n}, \frac{my_2 + ny_1}{m + n} )$

A point on y axis is given by (0,y).Let,this point divides the line joining the given points in ratio a:1.

So,$\frac{8a - 4}{a + 1} = 0$

$8a - 4 = 0$

So,

$a = \frac{4}{8} = \frac{1}{2}$

Hence,y axis divides the line joining the given points in ratio a:1 or 1:2.