Question

Y completes a piece of work in 40

days. X and Y complete the same work in

25 days. In how many days X alone will

complete the same work​

Answer 1

Answer:

55/4days

Step-by-step explanation:

Let the total work be 1

Then, According to question X takes 25 days to do 1 work.

Then work done by X in 1 day=

25

1

Also according to question Y takes 20 days to do 1 work.

Then work doe by Y in 1 day=

20

1

Then total work done by both of them in 1 day =

20

1

+

25

1

=

100

9

Then total work done by both of them 5 days=

100

45

Then total work left =1−

100

45

=

100

55

Now, As Y can do 1 work in 25 days therefore,

Y can do

100

55

work in

100

55

×25 days

=

4

55

days