Question

y= cos(1-x) dy/dx =?

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Answer 1

$\boxed{Given}$

$y=cos(1-x)$

$\boxed{we, know}$

$\boxed{{\boxed{\frac{dcosx}{dx}=-sinx}}$

applying this over here, and further applying chain rule, we get-

$\frac{dcos(1-x)}{dx} \\=(-sin(1-x))(-1)\\=sin(1-x)$

ans. -sin(1-x)

Answer 2

Answer:

sin(1-x)

Step-by-step explanation:

Use chain differentiation for this..

Let (1-x) be y.

So it becomes

$\frac{d (\cos(z) )}{dx}$

and we know that

$\frac{d \cos(z) }{dx} = \frac{d \cos(z) }{dz} \times \frac{dz}{dx} \: \: \: {by \: chain \: rule}$

so

as d(cos z)/dz = -sin z = -sin(1-x)

and dz/dx = d(1-x)/dx = 0 - 1 = -1

so

Ans: -sin(1-x) X -1 = sin(1-x)