Question

Y=cos(√3x), than find dy/dx

Answer 1

Answer:

$-\sqrt{3}sin(\sqrt{3}x)$

Step-by-step explanation:

$y = cos(\sqrt{3}x)$

$\frac{dy}{dx} = \frac{dcos(\sqrt{3}x)}{dx}$ (diff. wrt. x)

$\frac{dy}{dx} = -sin(\sqrt{3}x)\frac{d\sqrt{3}x}{dx}$ (f(g(x))` = f`(g(x))g`(x))

$\frac{dy}{dx} = -\sqrt{3}sin(\sqrt{3}x)$

Answer 2

The derivative is  $\frac{dy}{dx} = -\sqrt{3}\sin(\sqrt{3}x)$

Step-by-step explanation:

Given : Function $y=\cos (\sqrt{x})$

To find : The derivative dy/dx ?

Solution :

$y=\cos (\sqrt{x})$

Derivate w.r.t. x,

$\frac{dy}{dx} = \frac{d(\cos(\sqrt{3}x))}{dx}$

$\frac{dy}{dx} = -\sin(\sqrt{3}x)\times \frac{d\sqrt{3}x}{dx}$

$\frac{dy}{dx} = -\sqrt{3}\sin(\sqrt{3}x)$

Therefore, the derivative is  $\frac{dy}{dx} = -\sqrt{3}\sin(\sqrt{3}x)$

#Learn more

Derivative of dy by dx​

https://brainly.in/question/15709745