Question

y = cos(5 – 3t).dy/dt=
(1) 5 sin (5 - 3t)
(4) -5 sin (5 - 3t)
(2) 3 sin (5 - 3t)
(4) -3 sin (5-3t)​

Answer 1

Answer:

3 sin (5 - 3t)

Explanation :

dy/dt = - sin ( 5 - 3t) × d( 5 - 3t) /dt

dy/dt = - sin ( 5-3t) ( - 3)

dy /dt = 3 sin ( 5 - 3t)

Answer 2

Answer:

(c) 3 sin (5 - 3t)

Explanation:

Given:

y = cos(5-3t)

To Find

$\dfrac{dy}{dt}$

[derivative]

Solution

$y = cos(5-3t)$

Differentiating on both sides

$\dfrac{dy}{dt}= \dfrac{d[cos(5-3t)] }{dt}$

$\dfrac{dy}{dt}= \dfrac{d[cos(5-3t)]}{dt} \times \dfrac{d (5-3t)}{dt}$

$\dfrac{dy}{dt}= - sin (5-3t) \times -3$

$\dfrac{dy}{dt}= 3 sin (5-3t)$