Question

y=cos(5-3t)then dy/dt=

Answer 1

$y = \cos(5 - 3t) \\ \\ \frac{dy}{dt} = \frac{d}{dt} ( \cos(5 - 3t) )$

$\frac{dy}{dt} = - \sin(5 - 3t) \times \frac{d}{dt} (5 - 3t)$

$\frac{dy}{dt} = - \sin(5 - 3t) \times ( - 3) \\ \\ \frac{dy}{dt} = 3 \sin(5 - 3t)$

Answer 2

$\huge\mathcal{\fcolorbox{cyan}{black}{\pink{ĄNsWeR࿐}}}$

$y = \cos(5 - 3t) \\ \\ \frac{dy}{dt} = \frac{d}{dt} ( \cos(5 - 3t) )$

$\frac{dy}{dt} = - \sin(5 - 3t) \times \frac{d}{dt} (5 - 3t)$

$\frac{dy}{dt} = - \sin(5 - 3t) \times ( - 3) \\ \\ \frac{dy}{dt} = 3 \sin(5 - 3t)$

HOPE SO IT WILL HELP......