Question

y=cos(5-3t) then dy/dx

Answer 1

HERE IS YOUR ANSWER -sin (5-3t)×-3

Answer 2

Answer:

The value of dy/dx for the given function is $3\sin(5-3t)\frac{dt}{dx}$.

Step-by-step explanation:

The given function is

$y=\cos(5-3t)$

Differentiate with respect to x.

$\frac{dy}{dx}=-\sin(5-3t)\times \frac{d}{dx}(5-3t)$       $[\because \frac{d}{dx}\cos x=-\sin x ]$

$\frac{dy}{dx}=-\sin(5-3t)\times(-3\frac{dt}{dx})$

$\frac{dy}{dx}=3\sin(5-3t)\frac{dt}{dx}$

Therefore the value of dy/dx for the given function is $3\sin(5-3t)\frac{dt}{dx}$.